Find value under root162 upon under root 2
Answers
Answered by
0
Answer:
Hey friend,
Here is the answer you were looking for:
\frac{ \sqrt{162} }{ \sqrt{2} } \\
Splitting we get,
= \frac{ \sqrt{2 \times 9 \times 9} }{ \sqrt{2} } \\ \\ = \frac{9 \sqrt{2} }{ \sqrt{2} } \\
On rationalizing the denominator we get,
= \frac{9 \sqrt{2} }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ \\ = \frac{9 \sqrt{2} \times \sqrt{2} }{ {( \sqrt{2} )}^{2} } \\ \\ = \frac{9 \times 2}{2} \\ \\ = 9
Step-by-step explanation:
Similar questions