Math, asked by Vsana9211, 7 months ago

Find value under root162 upon under root 2

Answers

Answered by aquakiller013
0

Answer:

Hey friend,

Here is the answer you were looking for:

\frac{ \sqrt{162} }{ \sqrt{2} }  \\  

Splitting we get,

=  \frac{ \sqrt{2 \times 9 \times 9} }{ \sqrt{2} }  \\  \\  =   \frac{9 \sqrt{2} }{ \sqrt{2} }  \\  

On rationalizing the denominator we get,

=  \frac{9 \sqrt{2} }{ \sqrt{2} }  \times  \frac{ \sqrt{2} }{ \sqrt{2} }  \\  \\  =  \frac{9 \sqrt{2}  \times  \sqrt{2} }{ {( \sqrt{2} )}^{2} }  \\  \\  =  \frac{9 \times 2}{2}  \\  \\  = 9

Step-by-step explanation:

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