Question

......find value when a+b+c=0​

Answer 1

Answer:

-3

Step-by-step explanation:

a+b+c = 0

So,

b+c = -a

c+a = -b

a+b = -c

Substitute the above in the equation

=> (-a)²/bc + (-b)²/ca + (-c)²/ab

=> a²/bc + b²/ca + c²/ab

=> a³/abc + b³/abc + c³/abc

=> (a³+b³+c³)/abc - (1)

We know that,

(a³+b³+c³) = (a+b+c)(a²+b²+c²-ab-bc-ac)-3abc - (2)

Put (2) in (1)

=> [(a+b+c)(a²+b²+c²-ab-bc-ac)-3abc]/abc

But a+b+c = 0

So we get, -3abc/abc = -3