find values of a and b so that the polynomial x^3-10x^2+ax+b is exactly divisible by (x-1) as well as (x-2)
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Answered by
4
f(x)=x^3-10x^2-ax+b
f(1)=1-10-a+b=b-a-9
b-a=9---------(1)
f(2)=8-40-2a+b
b-2a=32--------(2)
from (1) and (2)
a=-23
b=-14
f(1)=1-10-a+b=b-a-9
b-a=9---------(1)
f(2)=8-40-2a+b
b-2a=32--------(2)
from (1) and (2)
a=-23
b=-14
pawarbhargav7p8ar1a:
how is the answer 32 and 14 explain me that
sorry
how a=-23 and b=-14
Answered by
1
f(x)=x^3-10x^2-ax+b
f(1)=1-10-a+b=b-a-9
b-a=9---------(1)
f(2)=8-40-2a+b
b-2a=32--------(2)
from (1) and (2)
a=-23
b=-14
f(1)=1-10-a+b=b-a-9
b-a=9---------(1)
f(2)=8-40-2a+b
b-2a=32--------(2)
from (1) and (2)
a=-23
b=-14
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