Question

find values of f
(2x + 3) = 4x^2+12x+15​

Answer 1

Answer:

${4x}^{2} + 12x + 15 - 2x - 3 = 0 \\ {4x}^{2} + 10x + 12 = 0 \\ divide \: by \: 2 \\ {2x}^{2} + 5x + 6 = 0 \\ discriminant \: d \: = {b}^{2} - 4ac \\ = {5}^{2} - 4 \times 2 \times 6 \\ = 25 - 48 \\ = - 23 \\ since \: d \: is \: negative \\ so \: equation \: has \: no \: real \: root$

Answer 2

Answer:

-root of 5x+3

Step-by-step explanation: