Find values of k if area of triangle is 4 sq. units and vertices are
(k, 0), (4, 0), (0, 2)
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Answer:
ar(∆)={x1(y2-y3)+x2(y3-y1)+x3(y1-y2)
4={k(0-2)+4(2-0)+0(0-0)
4=-2k+8+0
4=2(-k+4)
2=-k+4
k=2
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