Question

Find values of k if area of triangle is 4 square units and
vertices are (k, 0), (4, 0), (0, 2)​

Answer 1

Answer:

2

1

∣

∣

∣

∣

∣

∣

∣

∣

K

4

0

0

0

2

1

1

1

∣

∣

∣

∣

∣

∣

∣

∣

=±4

K=(0−2)−0(0)+1(8)=±8

−2K+8=±8

−2K=8−8

−2K=0

K=0

or −2K=−8−8

2K=16

K=8

Step-by-step explanation:

2

1

∣

∣

∣

∣

∣

∣

∣

∣

K

4

0

0

0

2

1

1

1

∣

∣

∣

∣

∣

∣

∣

∣

=±4

K=(0−2)−0(0)+1(8)=±8

−2K+8=±8

−2K=8−8

−2K=0

K=0

or −2K=−8−8

2K=16

K=8