Question

Find values of p and q so that x^4+x^3+8x^2+px+q is divisible by x^2+1

Answer 1

compare the coefficients always when remainder is 0

Answer 2

Answer:

p=1 q=7

Step-by-step explanation:

When we divide p(x) = x⁴+x³+8x²+px+q by g(x) = x²+1 the remainder is (p-1)x+q-7.

We are told that p(x) is divisible by g(x), so the remainder should be equal to zero.

Therefore (p-1)x+q-7 = 0.

For this to happen (p-1)x should be equal to zero and q-7 should be zero.

So it will be 0x+0=0.

Hence (p-1)x=0x q-7=0.

p=1 q=7

So the value of p is 1 and q is 7.

HOPE IT HELPS

PLEASE MARK AS BRAINLIEST