find values of x and y in each figure
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(a). 105°+x=180°{linear pair]
x=180°-105°
x=75°
therefore,
x+y+45°=180°{Angle sum property of a triangle}
75°+y+45°=180°
y+120°=180°
y=180°-120°
y=60°
therefore, x=75°and y=60°
(b). x=75°{Vertically opposite angles}
y+x+40°=180°{Angle sum property of a triangle}
y+75°+40°=180°
y+115°=180°
y=180°-115°
y=65°
therefore, x=75°and y=65°
(c). angle BAC=x{vertically opposite angle)
angle ABC=x(Vertically opposite angle)
angle ACB=x(Vertically opposite angle)
Now In ∆ABC,.
angle BAC+Angle ABC+Angle ACB=180°{Angle sum property of a triangle}
x+x+x=180°
3x=180°
x=180°/3
x=60°
Again,
y+x=180°{linear pair]
y+60°=180°
y=180°-60°
y=120°
therefore, x=60° and y=120°
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