Question

find values of x and y in eq. x/a=y/b ; ax+by=a^2+b^2




please answer my question in detail

Answer 1

Question

find values of x and y in eq. x/a=y/b ; ax+by=a²+b^²

Solution

Given:-

• x/a = y/b

Or,

• bx - ay = 0 -----------(1)

And

• ax + by = a²+b² --------(2)

multiply by a in equ(1) and b in equ(2)

• abx - a²y = 0
• abx + b²y = b(a²+b²)

_________________Sub. it's

➛ -(a²+b²)y = -b(a²+b²)

➛ y = -(a²+b²)/-(a²+b²)

➛ y = b

keep value of y in equ(1),

➛ bx - a*b = 0

➛ bx = ab

➛ x = ab/b

➛ x = a

Thus

• value of x = a
• Value of y = b

________________

Verification

Keep value of x and y in equ(1)

➛ bx - ay = 0

➛ b*a - a*b = 0

➛ 0 = 0

L.H.S = R.H.S

That's proved.

Answer 2

Answer:

Step-by-step explanation: