Find values of x and y in the given diagram
Attachments:
Answers
Answered by
1
AB is || to CD (as seen in the diagram)
Therefore angle BPR= 65°= y
y= 65°
Angle PQC+ Angle PQR= 180°
80°+ Angle PQR= 180°
Angle PQR= 180°-80° = 100°
According to Angle sum property of a triangle ,
Angle PQR+ Angle PRQ+ Angle RPQ= 180°
100°+ 65° + Angle RPQ= 180°
165°+ Angle RPQ= 180°
Angle RPQ= 180°-165°= 15°
Angle RPQ= x= 15°
HOPE IT HELPS! ^_^
Therefore angle BPR= 65°= y
y= 65°
Angle PQC+ Angle PQR= 180°
80°+ Angle PQR= 180°
Angle PQR= 180°-80° = 100°
According to Angle sum property of a triangle ,
Angle PQR+ Angle PRQ+ Angle RPQ= 180°
100°+ 65° + Angle RPQ= 180°
165°+ Angle RPQ= 180°
Angle RPQ= 180°-165°= 15°
Angle RPQ= x= 15°
HOPE IT HELPS! ^_^
Similar questions