Question

Find values of x, y and z so that x^-2=y^-3=z^-6=1/64​

Answer 1

Answer:

$\implies$ ${\large\blue{\mathbb\fcolorbox{aqua}{darkblue}{Solution:-}}}$

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Given:-

x^-2=y^-3=z^-6=1/64

To find :-

x=?

y=?

z=?

Solve:-

x^-2=y^-3=z^-6=1/64

On comparing equation :-

$\implies$ ax^2 + bx + c = 0

$\implies$ X = 2

$\implies$ y = 3

$\implies$ c= 1

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