find vector A×vector B if B= 3i^+j^+2k^ and A =i^+3j^+2k^
Answers
Answered by
2
Answer:
Let
a
=3i+j+2k and
b
=2i−2j+4k.
Now angle between
a
and
b
be
cos
−1
(
∣
a
∣∣
b
∣
a
.
b
)=cos
−1
(
14
.
24
6−2+8
)=cos
−1
(
28
3
).
Answered by
4
Answer:
this is the Answer...........
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