`Find velocity of B with respect to ground
(1) u/2(2) u/4(3) u/6(4) u/8
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1
Answer:
6u^2/a
Explanation:
Let both will meet at point B
x=2ut+1/2at
2
x=ut+
2
1
(2a)t
2
So 2ut+
2
1
at
2
=ut+at
2
ut=
2
1
at
2
⇒t=
a
2u
So x=2u(
a
2u
)+
2
1
a(
a
2u
)
2
=
a
6u
2
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