find volume of 4m and 2m koh solution to be added 3litres of 2.5m koh solution
Answers
Answer:
How do I prepare 2M of KOH?
Molarity = no. of Moles / vol. Of soln in litres
No. Of Moles = Weight / Molecular weight
So,
Molarity = (Weight / Molecular weight) / (Vol . of soln in litres)
Weight = Molarity x Vol. Of soln in litres x Molecular weight
If you want to prepare 1 litre of 2 M soln, substitute Molarity as 2, Vol. Of soln in litres as 1 and the Molecular weight of KOH in Molecular weight
That will give you how much KOH you have to weight to prepare the concentration (in distilled water).
Preparing bases have to be done by weighing the required and the right amount and mixing in part of the whole volume of distilled water because it increases the volume of the water taken on dissolving and thereafter you can add more dist. water and make it upto 1 litre or whatever volume you want to prepare for.
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The volume of 4M KOH solution is 0.75 litres and Volume of 2M KOH solution is 2.25 litres.
The volume of 4M KOH solution is 0.75 litres and Volume of 2M KOH solution is 2.25 litres. GIVEN
Molarity of KOH solutions= 4M and 2M
Volume of Final KOH solution = 3 litres
Molarity of Final KOH solution = 2.5M
TO FIND
Volume of 4M and 2M KOH solution.
SOLUTION
We can simply solve the above problem as follows;
Let the volume of 4M KOH solution = V1
The volume of 2M KOH solution = V2
According to the Question,
V1 + V2 = 3 (equation 1)
V1 = 3-V2
We know that,
Molarity = moles/Volume of solution
moles of 4M KOH solution = 4V1
Moles of 2M KOH solution;
Molarity = moles/V2
Moles of 2M KOH solution = 2V2
Molarity of final solution = Moles of solute/Volume of solution
Moles of solute = 2.5 × 3 = 7.5 moles.
Therefore,
4V1 + 2V2 = 7.5 (Equation 2)
Putting the value of V1
4(3-V2) + 2V2 = 7.5
12 - 4V2 + 2V2 = 7.5
-2V2 = 7.5-12
V2 = 4.5/2 = 2.25 L
V1 = 3-2.25 = 0.75 L
Hence, The volume of 4M KOH solution is 0.75 litres and Volume of 2M KOH solution is 2.25 litres.
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