Find volume of cone whose height is 24m and curved surface area is 550m sq
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given h=24cm
csa of cone=550cm^2 csa of cone=pi*r*l
pi*R*l=550
r*l=550*7/22
r*l=175
r=175/l
now we know that
l^2=r^2+h^2
l^2=(175/l)^2+24^2
576=l^2–30625/l^2
576=l^4–30625/l^2
l^4–576l^2–30625=0
then suppose x=l^2
then the eq is
x^2–576x-30625=0
x^2–625x+49x-30625=0
x(x-625)+49(x-625)=0
therefore x=625
l=(x)^1/2
l=25cm
r=175/25
r=7cm
volume of cone =1/3 pi*r^2*h
1/3*22/7*49*24
1232cm^3
thus we got the answer.
csa of cone=550cm^2 csa of cone=pi*r*l
pi*R*l=550
r*l=550*7/22
r*l=175
r=175/l
now we know that
l^2=r^2+h^2
l^2=(175/l)^2+24^2
576=l^2–30625/l^2
576=l^4–30625/l^2
l^4–576l^2–30625=0
then suppose x=l^2
then the eq is
x^2–576x-30625=0
x^2–625x+49x-30625=0
x(x-625)+49(x-625)=0
therefore x=625
l=(x)^1/2
l=25cm
r=175/25
r=7cm
volume of cone =1/3 pi*r^2*h
1/3*22/7*49*24
1232cm^3
thus we got the answer.
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