find volume of cylindrical pipe whose length is 4.52m and radious of base is 2.52cm
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C.Q: the radius of base should be 2.52m.
let length of cylinderical pipe
h = 4.52m
radius of its base = 2.52m
volume of cylinderical pipe
= πr^2h
= 22×(2.52)^2 × 4.52 / 7
= 90.21 m^3
Answer:
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volume of cylinderical pipe = 90.21 m^3
let length of cylinderical pipe
h = 4.52m
radius of its base = 2.52m
volume of cylinderical pipe
= πr^2h
= 22×(2.52)^2 × 4.52 / 7
= 90.21 m^3
Answer:
---------------
volume of cylinderical pipe = 90.21 m^3
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