Question

Find wave number of limiting line of Lymen series for H-atom

Answer 1

Its very simple..

Use this formula, Wave number = R [(1/n1^2) - (1/n2^2)] * Z^2

Here, n1 is the orbit corresponding to the series. In case of our question, Balmer series corresponds to 2.

n2 is any other higher orbit. In the present case, the limiting line is from infinity (∞).

As the atom is a hydrogen atom, Z=1.

R is the Rydberg Constant, R=109677 cm-1.

Now substitute all the values and you will get an approximate answer as, 27419 cm-1.

Hope it Helps :-)



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