Question

Find weight of mno2 reduced by 25 ml of 0.16 n oxalic acid

Answer 1

Explanation:

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Here's ur ans.:::::::

Given : N = 0.16 N

V = 35 ml

M = ?

we have

N = M×1000/V

0.16 = M×1000/35

.°. M = 0.16×35/1000

.°. M = 0.0056 g

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