Question

find weight of oxygen in 1*10^22 molecule of CuSO4.5H2O​

Answer 1

Answer:

4.144g

Explanation:

Number of molecules = 1\times 10^{22}

Moles of CuSO_4.5H_2O=\frac{1\times 10^{22}}{6.022\times 10^{23} mol^{-1}}=0.0166 mol

Moles=\frac{Mass}{\text{Molar mass}}

0.0166=\frac{Mass}{249.68 g/mol}

Mass of copper sulfate pentahydrate =4.144 g

The mass of 1\times 10^{22} molecules of copper sulfate pentahydrate is 4.144 g.