Question

Find what sum will amount to rupees 738 10 in 2 years at 10% per annum compound interest

Answer 1

$\bigstar \mid$ GIVEN :

• P(principal) = ₹73810.
• T(time) = 2 years.
• R(rate %) = 10%. p.a.

$\bigstar \mid$ TO FIND :

• The compound interest after the given cases.

$\bigstar$ SOLUTION :

we know that,

$\bf \implies \: amount \: = p (1 + { \frac{rate\%}{100} )}^{n} \\ \sf \to \: 73810 \times ( 1 + \frac{1 \cancel0}{10 \cancel0} {)}^{2} \\ \sf \to \: 73810 \times ( {1 + \frac{11}{10} )}^{2} \\ \sf \to \: 7381 \cancel0 \times \frac{11}{10} \times \frac{11}{1 \cancel0} \\ \bf \therefore \: amount \to 89310.1$

HENCE,

C. I. = ₹1,63120.1 ans.

Answer 2

Step-by-step explanation:

CA=p(1+R%/100)^T

73810 = p(1+10/100)^2

73810 = p× 1.21

78310/1.21 = p

61000=p

p=61000