Question

Find what value of k 2x + 3y = 4 and ( k + 2 ) x + 6y = 3k + 2 will have infinite many Solutions ?

Don't post irrelevant answer .​

Answer 1

Step-by-step explanation:

a1/a2=b1/b2=c1/c2

2/(k+2)=3/6=4/3k+2

we take

2/(k+2)=3/6

(cross multiplication)

3(k+2)=6(2)

3k +6=12

3k =12-6

3k =6

k=3/6

k=2

Answer 2

For a pair of linear equations, ifa/a2 = b / b2 = c / c2

2/k+2 = 3/6

= 4/3k+2 2/k+2

=4/3k +2 2( 3k + 2)

= 4( k + 2) 6k + 4

= 4k + 8 6 k - 4 k

= 8-4 2 k

=4 k = 2.

Hence, to have infinite solutions, k=2