Question

Find wheather -2x+3x+2=0 have real roots...if real roots exists,find them​

Answer 1

Step-by-step explanation:

-2x+3x+2=0

X+2=0x=0/2

Answer 2

Answer:

D=

${b}^{2} - 4ac \\ = {3}^{2} - 4 \times - 2 \times 2 \\ = 9 + 16 \\ = 25$

D=25

It has real roots.

They are

$= \frac{ - b + \sqrt{d} }{2a} \\ = = \frac{ - 3 + \sqrt{25} }{ - 4} \\ = \frac{ - 3 + 5}{ - 4} \\ \frac{ - 1}{2}$