find where is the mistake
0=0
(20-20) = (20)^2 - (20)^2
1(20-20) = (20-20) (20+20)
1 = (20-20) (20+20) / (20-20)
1 = 40
?????
howww
Anonymous:
(20)^2 = 20 × 20 but it is given that 20 +20
and in rhs when 20 - 20 is transported to lhs it becomes division
yeh it is the identity used a^2 -b^2 =(a+b) (a-b)
yeah sry everything convyed to Me in a different way
ok
then try once again nd answer it
Answers
Answered by
1
bro the wrong step is in 3rd step
1(20-20) =(20-20)/(20+20)
then (20-20)=0
1(0)=(0)/40
0=0
so this is solution
pls mark as brain list
1(20-20) =(20-20)/(20+20)
then (20-20)=0
1(0)=(0)/40
0=0
so this is solution
pls mark as brain list
no
it is wrong seee it once again
and find where is the mistake
it is brain less
it us correct man
try ur self
Answered by
6
Hi there
Your answer is :-
0 = 0 ( Correct )
( 20-20 ) = (20)^2 - (20)^2 ( Correct )
1 (20-20) = (20-20) (20+20) ( Wrong )
( 1 (20-20) = (20-20) (20+20) )
( 0 = 0 Note :- Anything multiplied with zero is zero . )
1 = (20-20) (20+20) / (20-20) ( Wrong )
( ( 20 - 20 ) = 0 , Note :- Anything multiplied with zero is zero )
So (20-20) (20+20) / (20-20) = 0
1 = 40
Thank You
Your answer is :-
0 = 0 ( Correct )
( 20-20 ) = (20)^2 - (20)^2 ( Correct )
1 (20-20) = (20-20) (20+20) ( Wrong )
( 1 (20-20) = (20-20) (20+20) )
( 0 = 0 Note :- Anything multiplied with zero is zero . )
1 = (20-20) (20+20) / (20-20) ( Wrong )
( ( 20 - 20 ) = 0 , Note :- Anything multiplied with zero is zero )
So (20-20) (20+20) / (20-20) = 0
1 = 40
Thank You
but why are u solving the bracket
its our own choice to solve it or not
the process is not wrong at all
but there is a one mistake
find it
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