find whether 0 is the term of ap 40,37,34 ,31
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Answered by
4
Formula
0=a+(n-1)d
0=40+(n-1)-3
0=40+(-3n+3)
0=40-3n+3
-40-3=-3n
-43=-3n
43=3n
43/3=n
It is in fraction so zero can't be in term of ap
0=a+(n-1)d
0=40+(n-1)-3
0=40+(-3n+3)
0=40-3n+3
-40-3=-3n
-43=-3n
43=3n
43/3=n
It is in fraction so zero can't be in term of ap
Answered by
5
0=a+(n-1)d
0=40+(n-1)-3
0=40-3n+3
3n=43
n=43/3
so 0 is not any term of AP
0=40+(n-1)-3
0=40-3n+3
3n=43
n=43/3
so 0 is not any term of AP
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