Question

Find whether 8x²+2x-3=0 have real roots..If real roots exists,find them.​

Answer 1

Answer:

easy

we know that

b^2_4ac=2*2-4*8*(-3)

=4-8*(-12)

=4+76

=80

so the value is positive so

the roots of the equation have real and distinct roots...

roots of the equation are....

8x^2+6x-4x-3=0

8x^2-4x+6x-3=0

4x(2x-1)+3(2x-1)=0

(4x+3)(2x-1)=0

x=-3/4, x=1/2

Answer 2

$8 {x}^{2} + 2x - 3 \\ 8 {x}^{2} - 4x + 6x - 3 \\ 4x(2x - 1) + 3(2x - 1) \\ (4x + 3)(2x - 1)$