Find whether P is equal to 2 and P is equal to 3 and solutions of the equation 7(p+2)=5 (p+4) justify
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Case - i
P=2
7(P+2)=5(P+4)
L.H.S.
7(P+2)
= 7(2+2) [After putting the value of P.]
= 7*4
= 28
R.H.S.
5(P+4)
= 5(2+4) [After putting the value of P.]
= 5*6
= 30
Hence, L.H.S. is not equal to R.H.S.
Case-II
P=3
7(P+2)=5(P+4)
L.H.S.
7(P+2)
= 7(3+2) [After putting the value of P.]
= 7*5
= 35
R.H.S.
5(P+4)
= 5(3+4) [After putting the value of P.]
= 5*7
= 35
L.H.S.=R.H.S. (Hence, proved.)
So, the value of P is 3
(Ans): 3.
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