Math, asked by randhawamanik582, 3 months ago

Find whether the equation has real roots. If real roots exists, find them:                    8x2+2x-12=0​

Answers

Answered by Abhinav3583
0

Answer:

This is an oxidation-reduction (redox) reaction:

4 NV + 4 e- → 4 NIV

(reduction)

2 O-II - 4 e- → 2 O0

(oxidation)

Hg(NO3)2 is an oxidizing agent, Hg(NO3)2 is a reducing agent.

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Answered by GraceS
1

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HERE IS UR ANSWER

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8 {x}^{2}  + 2x - 12 = 0 \\ 4 {x}^{2} + x - 6 = 0  \\ d =  {b}^{2}  - 2ac \\  =  {1}^{2}  - 4( - 6)(4) = 1 + 96 = 97 \\ x =  \frac{ - b - d}{2a}   \: or \: =   \frac{- b + d}{2a}  \\   = x =  \frac{ - 1 - 97}{8}  \: and \: x =  \frac{ - 1 + 96}{8}  \\  x=  \frac{ - 98}{8}  \:  =  \frac{49}{4} and \: x =  \frac{95}{8}

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