Question

Find, whether the given values are the roots of the given quadratic equation or not in each of the following quadratic equations:
$2x ^{2} - 3x - 2 = 0 \\ x = 2 \: and \: x = 3$
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Answer 1

Answer:

${2x}^{2} - 3x - 2 = 0 \\ (x - 2) \times (2x + 1) = 0 \\ x - 2 = 0 \: or \: x = 2 \\ 2x + 1 = 0 \: or \: 2x = - 1 \: or \: \\ x = \frac { - 1}{2}$

Answer 2

Answer:

Answer:

\begin{gathered} {2x}^{2} - 3x - 2 = 0 \\ (x - 2) \times (2x + 1) = 0 \\ x - 2 = 0 \: or \: x = 2 \\ 2x + 1 = 0 \: or \: 2x = - 1 \: or \: \\ x = \frac { - 1}{2} \end{gathered}

2x

2

−3x−2=0

(x−2)×(2x+1)=0

x−2=0orx=2

2x+1=0or2x=−1or

x=

2

−1