find whether (x+2) is a factor of x⁴- 16 or not
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Answered by
1
Answer
x+2=0
x= -2
f(x)=(-2)^2 - 16
0 = 4-16
0 = -12
Since 0 is not equal to -12 , the (x+2) is not a factor
Answered by
0
Answer:
Yes
Step-by-step explanation:
x^4 - 16 = (x^2)^2 - (4)^2
= (x^2 + 4)(x^2 - 4) (a^2 - b^2 = (a+b)(a-b) )
= (x^2 + 4)( (x)^2 - 2^2 )
= (x^2 + 4)(x + 2)(x - 2)
Hence, x+2 is a factor of x⁴- 16
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