Question

find which is quadric equation?
a)2x(x-1)=2x^2 - 3x
b)x(x+2)=3x^2+4
c)2x^2-5x+6=2x(x+5)
you have dare to solve this?​

Answer 1

Answer:

a) 2x(x-1)=2x^2 - 3x

2x²-2x = 2x²- 3x

2x²- 2x² = -3x+2x

0 = -x

b) x(x+2)=3x^2+4

x²+2x = 3x²+4

3x²+4-x²-2x = 0

2x²- 2x+4 = 0

c) 2x^2-5x+6=2x(x+5)

2x²-5x+6 = 2x²+10x

2x²-5x+5-2x²-10x = 0

-15x+5 = 0

it can be seen that option (b) is of the form ax²+bx+c = 0 , which is standard form of quadratic equation

Hence , option (b) is correct..

Step-by-step explanation:

hope it helps you

have a nice day ahead