Question

find work done by friction for displacement s​

Answer 1

Explanation:

see attachment..

hope it helps..

plz mark as brainliest... please

Answer 2

Answer:

Work done by friction for displacement S is  $-\mu_k(Fsin\ \theta+mg)S$ .

Explanation:

We know , work done by friction force is given by :

$W=F.S\\W=FS cos\ 180^{\circ}\\W=-FS$

Here , F is frictional force .

Now , we know frictional force is the product of coefficient of friction into normal reaction .

Here normal reaction is sum of vertical component of force F abd gravitational force .

Therefore , $N=Fsin\ \theta +mg$  

So , $F=\mu_k(Fsin\ \theta+mg )$

Therefore , work done is :

$W=-\mu_k(Fsin\ \theta+mg)S$

Work done by friction for displacement S is  $-\mu_k(Fsin\ \theta+mg)S$ .