Question

Find write pythagorem triplet whose one member is 37

Answer 1

Answer:

As we know 2m, m 2 + 1 and m2 - 1 form a Pythagorean triplet for any number, m > 1.

Let's assume

M^2+1=37

Then, M^2=36

And M=6

Now put the value of M

2M = 12

M^2+1=37

M^2-1=35

The triplets are 37, 35 and 12

Answer 2

Answer:

Let m=37

second member =m²-1/2

=37²-1/2

=1369-1/2

=1368/2

=684

third member. =m²+1/2

=37²+1/2

... =1369+1/2

=1370/2

=685

the required Pythagorem triplet is(37,684,685)