Question

Find x...
1÷2x-3+1÷x-5=1
Plzz help

Answer 1

   

$1\div2x-3+1\div x-5=1 \\ \\ \frac{1}{2x}-3+\frac{1}{x}-5=1 \\ \\ \frac{1}{2x}+\frac{1}{x}-8=1 \\ \\ \frac{x+2x}{2x^2}=1+8 \\ \\ \frac{3x}{2x^2}=9 \\ \\ \frac{3}{2x}=9 \\ \\ 2x=\frac{3}{9} \\ \\ 2x=\frac{1}{3} \\ \\ x=\bold{\frac{1}{6}}$

$\frac{1}{6}\ \sf{is the actual answer. \\ \\ If you've doubt, please do it in a calculator. Don't forget to take} \ \frac{1}{6}\ \sf{in a bracket.} \\ \\ \\ Plz mark it as the brainliest. \\ \\ \\ Thank you. :-)$