Question

find x,1/49×7power2x×343power5=7".​

Answer 1

Answer:

1/49  x  7^2x  x  343 ^5 = 7^1

49^-1  x  7^2x  x  7^3 = 7^1

7^(2)-(1) x 7^2x x 7^3 = 7^1

7^1 x 7^2x x 7^3 = 7^1

[as a^m + a^n = a^m+n]

7^1+2x+3 = 7^1

as the bases (7) are same on both sides

hence it will cancel out and only the powers will become the bases.

1+2x+3 = 1

2x+4 = 1

2x = 1-4

2x = -3

x = -3/2

hope it helps!

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Step-by-step explanation: