Question

find x^2+1/x^2,x^4+1/x^4,x^3+1/x^3,x^3-1/x^3 ,√x+1/√x if x=3+2√2​

Answer 1

Answer:

x^2+1/x^2

:-(3+2√2)^2+1/(3+2√2)^2

:-(9+12√2+8+1)/(3+2√2)^2

:-(18+12√2)/(3+2√2)^2

:-6/3+2√2

:-(6/3+2√2)×(3-2√2)/(3-2√2)

:-6(3-2√2)/(3+2√2)×(3-2√2)

:-6(3-2√2)/9-4×2

:-6(3-2√2)/9-8

:-6(3-2√2)/1

:-18-12√2

x^4+1/x^4

:-(3+2√2)^4+1/(3+2√2)^4

:-577+408√2+1/577+408√2

:-578+408√2/577+408√2

:-578+408√2/577+408√2×577-408√2/577-408√2

:-(333506-235824√2+235416√2-332928). /577^2-408^×2

:-578-408√2/577^2-2×408^2

Answer 2

Answer:

Step-by-step explanation:

X+1 +X+2 X+3 =

X+1 + X+2 + X+3

Substitute the 1 to 3

X+X+2+X+3-1

=2X+2+X+2

3X+4

X=4÷3

X=1.333333

Substitute X into 1.333333

1.333333+1+1.333333+2+1.333333+3=

2.333333+3.333333+4.333333=

9.999999