Question

Find x 2+ y 2 if ,x+y=12 and xy=32

Answer 1

squaring both sides,
(x+y)2=(12)2
x2 + y2+ 2xy= 144
x2+y2+2(32)=144
x2+y2=144-64
x2+y2=80

Answer 2

Answer:

given =.x+y = 12

xy=32

find $x^{2}+y^{2}=?$

x+y = 12 (squaring on both side)

$x^{2}+y^{2}+ 2xy = 144 \\ x^{2}+y^{2}+2×32 = 144 \\ x^{2}+y^{2}=.144-2×32 \\ x^{2}+y^{2}=80$