Math, asked by heyshona, 1 year ago

find x^2+y^2+z^2 if x^2+xy+xz=135,y^2+yz+yx=351 and z^2+zx+zy=243.

Answers

Answered by smartAbhishek11
21
Dear Student,
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Please find below the solution to the asked query:

Given : x2 + xy + xz  = 135             --- ( 1 ) ,

y2 + yz + yx  = 351                        --- ( 2 )

And

z2 + zx + zy  = 243                        --- ( 3 )

Now we add equation 1 , 2 and 3 and get

x2 + y2  + z2  + 2 xy + 2 yz  + 2 zx  = 729 

( x + y + z )2  = 729                                 ( We know : ( x + y + z )2  = x2 + y2  + z2  + 2 xy + 2 yz  + 2 zx )

( x + y + z )2  = 272

x + y + z  = 27                                        --- ( 4 )

Now we take equation 1 : x2 + xy + xz  = 135

x ( x + y + z ) = 135  , Substitute value from equation 4 and get 

27 x  =  135

x = 5

And we take equation 2 : y2 + yz + yx  = 351

y ( x + y + z ) = 351  , Substitute value from equation 4 and get 

27 y  =  351

y = 13

And we take equation 3 : z2 + zx + zy  = 243

z ( x + y + z ) = 243  , Substitute value from equation 4 and get 

27 z  =  243

z = 9

Therefore,

Value of x2 + y2 +z2  = 52  + 132 + 92 =  25 + 169 + 81  = 275                                       ( Ans )

Hope this information will clear your doubts about topic.

If you have any more doubts just ask here on the forum and ask me smart Abhishek will try to help you out as soon as possible.

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Answered by Jenifercooper7897
1

Answer:

275

Step-by-step explanation:

Given : x2 + xy + xz  = 135             --- ( 1 ) ,

y2 + yz + yx  = 351                        --- ( 2 )

And

z2 + zx + zy  = 243                        --- ( 3 )

Now we add equation 1 , 2 and 3 and get

x2 + y2  + z2  + 2 xy + 2 yz  + 2 zx  = 729 

( x + y + z )2  = 729                                 ( We know : ( x + y + z )2  = x2 + y2  + z2  + 2 xy + 2 yz  + 2 zx )

( x + y + z )2  = 272

x + y + z  = 27                                        --- ( 4 )

Now we take equation 1 : x2 + xy + xz  = 135

x ( x + y + z ) = 135  , Substitute value from equation 4 and get 

27 x  =  135

x = 5

And we take equation 2 : y2 + yz + yx  = 351

y ( x + y + z ) = 351  , Substitute value from equation 4 and get 

27 y  =  351

y = 13

And we take equation 3 : z2 + zx + zy  = 243

z ( x + y + z ) = 243  , Substitute value from equation 4 and get 

27 z  =  243

z = 9

Therefore,

Value of x2 + y2 +z2  = 52  + 132 + 92 =  25 + 169 + 81  =275

Thanks

Aarohi

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