Find x,27 power x =9/3x
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given:-
27^x=9/3x
now 27 can be written as 3^3
so
(3)^3x=9/3x
3x ×3^3x=9
9 can be written as 3^2
whenever a same number has different powers it's power get added
so
3^3x+1=3^2
[ 3 gets cancelled]
3x+1=2
x=1/3
hope helps
given:-
27^x=9/3x
now 27 can be written as 3^3
so
(3)^3x=9/3x
3x ×3^3x=9
9 can be written as 3^2
whenever a same number has different powers it's power get added
so
3^3x+1=3^2
[ 3 gets cancelled]
3x+1=2
x=1/3
hope helps
SmãrtyMohït:
what happened
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