Math, asked by sk1602059, 1 day ago

find ✓x + ✓2x + ✓3x write your answer​

Answers

Answered by attackrates
1

 \sqrt{2x + 9}  +  x = 13 \\  \\  \sqrt{2x + 9}  = 13 - x \\  \\ on \: squring \: we \: get \\ 2x + 9 = {x}^{2}  + 169 - 26x \\   =  {x}^{2} + 160 - 28 \times  = 0  \\   =  {x}^{2}  - 20 - 8x  + 160 = 0 \\  =  ({x}^{2}  - 20)(x - 8) = 0 \\ x = 20 \: ro \: x = 8 \\  \\ but \: x = 20 \: does \: not \: satisfy \\ ans \: is \: x = 8

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