Math, asked by imperialvx24, 11 months ago

find x. 2x×8^1/5=2^1/5​

Answers

Answered by Hiteshbehera74
1

2x {8}^{ \frac{1}{5} }  =  {2}^{ \frac{1}{5} }  \\ x \times  {2}^{1}  \times  {2 }^{ {3}^{ \frac{1}{5} } }  =  {2}^{ \frac{1}{5} }  \\ x \times  {2}^{1}  \times  {2}^{ \frac{3}{5} }  =  {2}^{ \frac{1}{5} }  \\ x \times  {2}^{ \frac{8}{5} }  =  {2}^{ \frac{1}{5} }  \\ x =  \frac{ {2}^{ \frac{1}{5} } }{ {2}^{ \frac{8}{5} } }  \\ x =  {2}^{ \frac{1}{5} }  -  {2}^{ \frac{8}{5} }  \\ x =  {2}^{ \frac{1 - 8}{5} }  \\ x =  {2}^{  \frac{ - 7}{5} }  \\ x =  \frac{1}{ {2}^{ \frac{7}{5} } }

Answered by warylucknow
1

The value of x is \frac{1}{2}(\frac{1}{4})^{1/5}.

Step-by-step explanation:

The expression is:

2x\times 8^{1/5}=2^{1/5}

Solve for x as follows:

2x\times 8^{1/5}=2^{1/5}

2x=(\frac{2}{8})^{1/5}

2x=(\frac{1}{4})^{1/5}

x=\frac{1}{2}(\frac{1}{4})^{1/5}

Thus, the value of x is \frac{1}{2}(\frac{1}{4})^{1/5}.

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