Question

find: [-x-2y+6z]^2 plz help me the person who help me I'll mark him/her brainliest

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$QUESTION : {( - x - 2y + 6z)}^{2} \\ By \: using \: identity - {( a + b + c )}^{2} \\ Then, \: \: \\ a = - x \: ; \: b = - 2y\: ;\: \: c = 6z \\ so \\ {( a + b + c )}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ac \\ \implies \:\:\:\:\:\:\:= {( - x)}^{2} + {( - 2y)}^{2} + {6z}^{2} + 2 \times ( - x)( - 2y) + 2 \times ( - 2y)(6z) + 2 \times ( - x)6z \\ \implies\:\:\:\:\:\:\: = {x}^{2} + 4{y}^{2} + 36 {z}^{2} + 4xy - 24yz - 12xz$