find x^3 + y^3 if x+y =10 and xy = 21
Answers
Answered by
1
Step-by-step explanation:
x³+y³=(x+y)³-3xy(x+y)
x³+y³=1000-3(21)(10)
x³+y³=1000-630
x³+y³=370
Answered by
0
Answer:
hey mate there's your answer
given x+y=10 and xy=21
we know that,
(x+y)^3=x^3+y^3+3xy(x+y)
put those values in above equation.
(10)^3=x^3+y^3+3(21)(10)
1000 =x^3+y^3+630
x^3+y^3=1000-630
x^3+y^3=370
hope it helps you .............
thank you!!!
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