find x- (4/7)³ ÷ (7/4)^-5 = (4/7)^x-2
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Answer:
(4/7)³ ÷ (7/4)⁵ = (4/7)^(x - 2)
(4/7)³ ÷ (4/7)-⁵ = (4/7)^(x - 2) (4/7 raised to -5)
Now, by a^m ÷ a^n = a^ (m - n),
3 - (-5) = x - 2
3 + 5 = x - 2
x = 3 + 5 + 2
x = 10.
Step-by-step explanation:
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