Question

find x- (4/7)³ ÷ (7/4)^-5 = (4/7)^x-2​

Answer 1

(4/7)³ ÷ (7/4)⁵ = (4/7)^(x - 2)

(4/7)³ ÷ (4/7)-⁵ = (4/7)^(x - 2) (4/7 raised to -5)

Now, by a^m ÷ a^n = a^ (m - n),

3 - (-5) = x - 2

3 + 5 = x - 2

x = 3 + 5 + 2

x = 10.

hope you got the best answer

Answer 2

$\large\red{\underline{{\boxed{\textbf{your answer}}}}}$

$( 4 \div 7 ) ^{3} \times( 4 \div 7) ^{ - 5} =( 4 \div 7) ^{x - 2} \\ (4 \div 7) ^{ - 2} =(4 \div 7) ^{x - 2}$

$comparing \: the \: power \: of \: same \: \\ base$

$- 2 = x - 2 \\ - 2 + 2 = x \\ x = 0$

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