find x: (√5/3)^x-8 =(25/125)^2x-3
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Answered by
16
Answer:
root3/root5 can also be written as
(3/5)^1/2
now
(3/5)^(1/2×x+1)=125/27
(3/5)^(x+1)/2=(5/3)^3
=(3/5)^-3
now if base equal than power equal
(x+1)/2=-3
x+1=-3×2
x+1=-6
x=-6-1=-7
Answered by
2
root3/root5 can also be written as
(3/5)^1/2
now
(3/5)^(1/2×x+1)=125/27
(3/5)^(x+1)/2=(5/3)^3
=(3/5)^-3
now if base equal than power equal
(x+1)/2=-3
x+1=-3×2
x+1=-6
x=-6-1=-7
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