Math, asked by tharunrockmadurai, 11 months ago

find x
65=54x+105xx^{2} x^{2} x^{2} \geq \sqrt{x} \sqrt{x} x^{2}

Answers

Answered by jjaannuu
1

Answer:

Hii mate

your answer is

Step-by-step explanation:

65 = 54x + 105 x

65 = 159 x

(interchange the digits)

159 x = 65

x = 65 ÷ 159

so on you can calculate now !!

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