Math, asked by gangasingh355, 1 year ago

Find x : 7^2x+3=1


Please answer fast

Answers

Answered by zerodown1024
130
7^2x+3 = 1

[We know a^0 = 1]

So , we can write →

7^2x+3 = 1×7^0

or, 7^2x+3 = 7^0

[ a^m = a^n , then m=n]

or, 2x+3 = 0

or, 2x = -3

or, x = -3/2

Answer → Value of x = -3/2.
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Answered by snehitha2
106
Hi friend!!

7^2x+3 = 1

7^2x+3 = 7^0

Bases are equal. Exponents must be equal.

2x+3 = 0

2x = -3

x = -3/2

Hope it helps...
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