Find x : 7^2x+3=1
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Answered by
130
7^2x+3 = 1
[We know a^0 = 1]
So , we can write →
7^2x+3 = 1×7^0
or, 7^2x+3 = 7^0
[ a^m = a^n , then m=n]
or, 2x+3 = 0
or, 2x = -3
or, x = -3/2
Answer → Value of x = -3/2.
__________________________________
[We know a^0 = 1]
So , we can write →
7^2x+3 = 1×7^0
or, 7^2x+3 = 7^0
[ a^m = a^n , then m=n]
or, 2x+3 = 0
or, 2x = -3
or, x = -3/2
Answer → Value of x = -3/2.
__________________________________
Answered by
106
Hi friend!!
7^2x+3 = 1
7^2x+3 = 7^0
Bases are equal. Exponents must be equal.
2x+3 = 0
2x = -3
x = -3/2
Hope it helps...
7^2x+3 = 1
7^2x+3 = 7^0
Bases are equal. Exponents must be equal.
2x+3 = 0
2x = -3
x = -3/2
Hope it helps...
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