Question

Find x and y by rationalising the denominator 4+ √2 2+√2 = x - √y

Answer 1

Answer:

find the attached file for ans

Answer 2

$\bold{ \frac{4 + \sqrt{2} }{2 + \sqrt{2} } = x - \sqrt{y} } \\ \\ \bold{ = \: \frac{4 + \sqrt{2} }{2 + \sqrt{2}} \: \times \frac{2 - \sqrt{2} }{2 - \sqrt{2} } } \\ \\ \bold{ = \: \frac{4(2 - \sqrt{2} ) + \sqrt2{(2 - \sqrt{2} )} }{2(2 - \sqrt{2} ) + \sqrt2{(2 - \sqrt{2} )} } } \\ \\ \bold{ = \: \frac{8 - 4 \sqrt{2} \: \: + 2 \sqrt{2} - 2 }{4 - 2 \sqrt{2} \: \: + 2 \sqrt{2} - 2 } } \\ \\ \bold{= \: \frac{8 - 4 \: \: \cancel{\sqrt{2}} \: \: + \cancel{2 \sqrt{2} - 2 }}{4 - 2 \: \: \cancel{\sqrt{2} }\: \: + \cancel{2 \sqrt{2} - 2 }}} \\ \\ \bold{ = \: \frac{8 - 4}{4 - 2} } \\ \\ \bold{ = \: \frac { \cancel4 \: ²}{ \cancel2} } \\ \\ \bold{ = \: \frac{2}{1} } \\ \bold{ \frac{2}{1} = x - \sqrt{y} } \\ \\ \bold \red{x = 2 \: and \: y = \sqrt{1} \: \: \: ....ans}$

hope it helps you....

mark as brainliest plzz ❤️