Find x and y ff 2x+3y = 12, x-y-1=0
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Answered by
0
Answer:
2x+3y=12-----1
2(x-y-1=0)
= 2x-2y=2------2
Subtracting 1and 2 we gets,
2x+3y=12
2x-2y=2
___________
5y=10
y=2
Now,
2x-2y=2
2x-2×2=2
2x=6
x=3
Answered by
0
Answer:
2x+3y=12
x+3y=12*2
x+y=24*3
x+y=72
x-y-1=0
x-y=1
x=36
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