find x and y for
10/x+y+2/x-y=4
15/x+y-5/x-y=-2 using cross method
pls answer
Answers
Answered by
0
Step-by-step explanation:
10/x+y+2/x-y=4
(10x-10y+2x+2y) / (x+y)(x-y)=4
(12x-8y)/(x+y)(x-y)=4→(i)
15/x+y-5/x-y=-2
(15x-15y-5x-5y)/ (x+y)(x-y)=-2
(10x-20y)/ (x+y)(x-y)=-2→(ii)
(i)/(ii)→
{(12x-8y)/(x+y)(x-y)} / {(10x-20y)/ (x+y)(x-y)}= 4/(-2)
{(12x-8y)/(x+y)(x-y)}*{(x+y)(x-y)/(10x-20y)}= -2
(12x-8y)/(10x-20y)= -2
12x-8y= -20x+40y
32x= 48y
x= 48y/32
x=3y/2
y=2x/3
Similar questions