Math, asked by ravikumare, 5 days ago

find x and y for
10/x+y+2/x-y=4
15/x+y-5/x-y=-2 using cross method
pls answer

Answers

Answered by AB2004
0

Step-by-step explanation:

10/x+y+2/x-y=4

(10x-10y+2x+2y) / (x+y)(x-y)=4

(12x-8y)/(x+y)(x-y)=4→(i)

15/x+y-5/x-y=-2

(15x-15y-5x-5y)/ (x+y)(x-y)=-2

(10x-20y)/ (x+y)(x-y)=-2→(ii)

(i)/(ii)→

{(12x-8y)/(x+y)(x-y)} / {(10x-20y)/ (x+y)(x-y)}= 4/(-2)

{(12x-8y)/(x+y)(x-y)}*{(x+y)(x-y)/(10x-20y)}= -2

(12x-8y)/(10x-20y)= -2

12x-8y= -20x+40y

32x= 48y

x= 48y/32

x=3y/2

y=2x/3

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